SSC CGL exam pattern

The SSC CGL Examination consists of following phases – Tier 1, Tier 2 and Tier 3 (where ever required). Mainly it consists of two Phases i.e. Tier 1 and Tier 2.

In Tier I, there will be 200 multiple choice questions (MCQs) to be asked from 4 sections i.e. English, Reasoning, Quantitative Aptitude and General Awareness.

Each section has 50 questions and each question carry 1 mark and 0.25 marks are deducted for every wrong answer. The total duration of Tier 1 exam is 2 hours. Those who qualifies Tier 1 exam will appear for Tier 2 exam.

For Tier II, there will be two sections viz., English and Quantitative aptitude.

Quantitative aptitude consists of 100 multiple choice questions and each carry 2 marks. The duration of this exam will be 2 hours. In this exam 0.50 marks will be deducted as penalty for wrong answer.English section also carries 100 multiple choice questions of 2 marks each. The duration of this exam is 2 hours. In this 0.25 marks will be deducted as penalty for wrong answer.

The Tier III exam can be Computer Proficiency Test/ Skill Test (wherever applicable)/ Document Verification.

Note: The Interview component has been dispensed with. There will, therefore, be no interview.

Even though the sectional weightage for General Awareness is same as others, you still need a good strategy in order to maximize final scores. 

Job profile Statistical Investigator Grade

You are recruited for Statistical Investigator Grade II Post through SSC CGL Examination. Your career begins with designated of Junior Statistical Officer (JSO), which is, a Group B Central Civil Service Non-Gazetted Post of the Subordinate Statistical Service (SSS) Cadre under the Ministry of Statistics and Programme Implementation.

As a Junior Statistical Officer (JSO), there will be 2 areas where you will be working upon – Data Collection and Data Processing. The posted will be in the National Sample Survey Office (NSSO).

Data Collection JSO Job Profile is primarily an intensive field job. It is generally handled by the FOD (Field Operations Division) of the NSSO and the officers are expected to conduct surveys and data collection drives for different governmental schemes, programmes, socio-economic factors, urban surveys and price indexes.Data Processing JSO Job Profile is basically a desk job under the NSSO non-field operations department. Junior Statistical Officer working under this profile prepare extensive data reports for the different governmental Ministries/ Departments/ Organisation. The data compiled by them provides general estimates and parameters for the formulation of govt policies, schemes and programmes of the Government of India.

If the posting of a Statistical Investigator is in Ministries, the Officers have clerical job profile. They are in charge of drafting documents, preparing survey report requirements, data entry, tabulation, editing and compiling of existing data into reports and other similar responsibilities.

Approximation a game Know How ?

Approximation: An approximation is anything that is similar but not exactly equal to something else.

(i) Method of approximation for Addition & subtraction equation: Let us understand this method with an example:

Example. Find the approximate value of ‘x’ upto 3 digit:

4673.483 + 8494.867 – 7526.461 = x – 894.356 + 143.793

(a)2200.698(b) 4860.564 (c) 6500.699 (d) 3886.648

Step 1: Convert the exact values into approximate values.

4673.483  4700, 8494.867 8500, 7526.461 7500, 894.356  900, 143.793  100

Step 2: Put the value approximate values in the equation

4700 + 8500 – 7500 = x – 900 + 100

Step 3: After solving the equation

x = 6500

6500 is the approximate value of x. So, option(c) is very near about 6500.

(ii) Method of approximation for multiplication & Division equation: Let us understand this method with an example:

Example: What is the approximate value nearly to ‘x’?
89487  124 x 19808  594 x 40238  873 = x?
(a)1086888 (b) 1857122(c) 80388 (d) 549534

Step 1: Convert the exact values into approximate values.
89487  89500, 124  125, 19808  19800, 594  600, 
40238 40250, 873  875

Step 2: Put the approximate values in the equation.

Step 3: After solving the equation
x = 1086888.
1086888 is the approximate value of x. So, option (b) is very near about 1086888.

(iii) Method of approximation for square roots & cube roots:

Example: What is the approximate value of ‘x’?

(a)44 (b) 76 (c) 56 (d) 34

Step 1: Put the approximate values near the square root and cube root of an equation.
5342.045329,
5013.036  4913, 5847, 7734  , 10649.876 10648.

Step 2: Put the value approximate values in the equation.

Step 3: After solving the equation
x = 73 + 17-18+4

x = 76.
Note: To get the result very near about the exact answer we should always decrease or increase some quantities to make the balance.

We have discussed concepts of Simplification and Approximation techniques in our article.

Hope this was helpful

All the best!!!

Simplest way to Simplification

Rules of Simplification: Basic rule to solve any simplification equations is “VBODMAS”. To solve any simplification equation, we have to follow the above order.

V → Vinculum

B → Remove Brackets - in the order ( ), { }, [ ] 

Where, ( )→ common bracket or parentheses, { }→ braces , [ ] → square brackets

O → Of
D → Division

M → Multiplication

A → Addition

S → Subtraction

Note: At the time of opening of brackets, if a negative sign comes before the brackets then we have to change the sign of the expression inside the bracket.

Let us understand this concept with an example:

Example: Simplify:

= 894 + [87 - {182 ÷ 13 x 5 + 8 - (1-4)}]

= 894 + [87 – {182 ÷ 13 x 5 + 8 -(-3)}]

= 894 + [87 – {182 ÷ 13 x 5 + 8 +3}]

= 894 + [87 – {14 x 5 + 8 +3}]

= 894 + [87 – {70 + 8 +3}]

= 894 + [87 – {81}]

= 894 + [6]

= 900.

We have seen the simple method to solve the simplification problems, now we will discuss the approaches to solving the simplification problems by approximation.

Know more about numbers

Properties of number:

1. Commutative Property: This property tells us we can add and multiply numbers in any order.

(i) a + b + c = b + a + c

Ex.  3 + 5 + 6 = 5 + 3 + 6

In left hand side we add 3 & 5, and then we will get 8

In right hand side we add 5 & 3, and then we will also get 8.

8 + 6 = 6 + 8

14 = 14

L.H.S and R.H.S both are equal.

 

(ii) axbxc = bxcxa

5 x 6 x 7 = 6 x 7 x 5

In left hand side we multiply 5 & 6, and then we will get 30

In right hand side we add 6 & 7, and then we will also get 42.

30 x 7 = 42 x 5

210 = 210.

LHS and RHS both are equal.

 

2. Associative Property: Both addition and multiplication can be done with two numbers at a time.

(i)  a +(b + c)= (a + b) +c

Ex.  5 + (6 + 8) = (5 + 6) + 8

  5 + 14 = 11 + 8

19 = 19

Hence proved, LHS and RHS both are equal.

 

(ii)  ax (b x c) = (a x b) x c

Ex. 5 x (6 x 8) = (5 x 6) x 8

5 x 48 = 30 x 8

240 = 240

Hence proved, L.H.S and R.H.S both are equal.

 

3. Distributive Property: In this property "multiplication distributes over addition".

a x (b +c) = a x b + a x c

Ex. 5 x (6 + 8) = 5 x 6 + 5 x 8

5 x 14 = 30 + 40

70  = 70

Hence proved, L.H.S and R.H.S both are equal.

 

4. Identity property: It tells us that zero added to any number is the number itself. Zero is called the "additive identity." The identity property for multiplication tells us that the number 1 multiply by any number gives the number itself. The number 1 is called the "multiplicative identity."

Ex. a +0 = a

                       a.1 = a

5. Additive Inverse: The additive inverse of a number ‘a’ is the number that when added to ‘a’, yields zero. This number is also known as the opposite (number), sign change, and negation.

Ex.  a + (-a) = 0.

 

6. Multiplicative Inverse: It is reciprocal of a, denoted 1/a or a^-1.

Ex. a.1/a = 1

 

7. Additive Inverse: In this property, reverses the sign only.

Ex. a+ (-a) = 0.

 

Divisibility Rules: Divisibility means that you are able to divide a number evenly without using the long division.

Divisibility by 2: When the unit place digit of any number is 0,2,4,6 or 8 then the number is divisible by 2.

Ex. 10, 12, 1324, 13564, 434432, 9429372, etc.

 

Divisibility by 3: When the sum of digits of a number is divisible by 3 then the number is also divisible by 3.

Ex. 465981: 4+6+5+9+8+1= 33, which is divisible by 3, so 465981 must be divisible by 3.

 

Divisibility by 4: When the number formed by the last two digits of given number is divisible by 4 or it must be two or more zeros then the number is divisible by 4.

Ex.448, 1428, 33700, 4387920, etc.

 

Divisibility by 5: When the last digit of any number is either ‘5’ or ‘0’ is divided by 5.

Ex. 6742735, 3749370, 27629345, etc.

 

Divisibility by 6: When the number is divisible by 2 and 3 both then the number must be divisible by 6.

Ex. 356478, 82458474, 73834626, are divisible by 6.

 

Divisibility by 7: When the difference between the number formed by the digits other than the units digit and twice the units digit is either 0 or multiple of 7.

Ex. 798 is divisible by 7 because 79-2x8=79-16=63 is divisible by 7 and 798 is also divisible by 7.

 

Divisibility by 8: When the number formed by the last three digits of given number is divisible by 8 or it must be three or more zeros then the number is divisible by 8.

Ex. 848, 10128,323000, 438720, etc.

 

Divisibility by 9: When the sum of digits of a number is divisible by 9 then the number is also divisible by 9.

Ex. 39469581: 3+9+4+6+9+5+8+1= 45, which is divisible by 9, so 39469581 must be divisible by 9.

 

Divisibility by 11: When the sum of digits at odd and even places is equal or differs by a number divisible by 11, then the number is divisible by 11.

Ex. 7004844 is divisible by 11,  since

(Sum of digits at odd places) - (Sum of places at even places) = (7+0+8+4) - (0+4+4) = 19 - 8= 11.

Topics of the day – 2nd March 2016

1) Modi’s visit to Israel: India lines up defence deals worth $3 billion-

2) Delhi government launches HPV vaccine –

3) Government to move amendment to EPF tax proposal –

4) CM Jayalalitha Launches Arasu Internet Service –

5) Raychaudhury Takes Charge as RINL Director-

Question of 1 august 2015

Question for practice

1.       What is KYC?

1.       Know Your Cost

2.       Know Your Consumer

3.       Know Your Customer

4.       Know Your Court

5.       None of the above

2.       What is ROM?

1.       Read only Memory

2.       Read onetime Memory

3.       Read one Memory Card

4.       Ready only Memory

5.       None of the above

3.       Which is not a programming language?

1.       C

2.       C++

3.       COBAL

4.       FORTAN

5.       Windows

4.       7              12           22           37           57           ?

1.       80

2.       82

3.       88

4.       92

5.       None of the above

5.       11           16           23           32           43           ?

1.       66

2.       64

3.       52

4.       56

5.       None of the above

Answer : 1. (3) 2. (1) 3.(5) 4. (2) 5.(4)

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