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Study plan of SSC CGL Quantitative Aptitude

Do not try to study everything because if you try and study everything you will end up cramming your schedule and ultimately risk being under prepared.Accuracy and Speed are the keys for scoring maximum in this section.Give  1 hour daily for Quantitative Aptitude preparation.For the next 2-3 days, go through basic concepts and questions for topics stated above.Then take up each topic for 3 days and solve maximum questions possible on that topic.While doing the above exercise, solve at least 50 questions everyday.Start giving Mock Tests. Identify topics you are weak in and again attempt those topics.Mock Tests will also help you prepare a timing strategy.Talk to experts about those topics and get your doubts solved.Practice Practice Practice. All the BEST.

Syllabus of SSC CGL Quantitative Aptitude

SSC CGL Quantitative Aptitude Section: Pattern

No. of questions: 50
Total marks: 50
Marks per correct answer:1

Negative Marking for incorrect answer: 0.25
Syllabus 

1) Series

2) Data Sufficiency

3) Data Interpretation.

4)Whole numbers & Decimals

5) Ratio & Proportion

6) Percentages

7) Averages

8) Simple and Compound Interest

9) Profit and Loss, Discount, Partnerships

10) Mixture and Alligation

11) Time and distance, Time & Work

12) Basic algebraic identities of School Algebra & Elementary surds

13) Graphs of Linear Equations

14) Geometry

15) Trigonometric ratio

16) Degree and Radian Measures

17) Complementary angles

18) Heights and Distance

19) Histogram, Frequency Polygon, Pie Chart, Bar Chart.

Approximation a game Know How ?

Approximation: An approximation is anything that is similar but not exactly equal to something else.

(i) Method of approximation for Addition & subtraction equation: Let us understand this method with an example:

Example. Find the approximate value of ‘x’ upto 3 digit:

4673.483 + 8494.867 – 7526.461 = x – 894.356 + 143.793

(a)2200.698(b) 4860.564 (c) 6500.699 (d) 3886.648

Step 1: Convert the exact values into approximate values.

4673.483  4700, 8494.867 8500, 7526.461 7500, 894.356  900, 143.793  100

Step 2: Put the value approximate values in the equation

4700 + 8500 – 7500 = x – 900 + 100

Step 3: After solving the equation

x = 6500

6500 is the approximate value of x. So, option(c) is very near about 6500.

(ii) Method of approximation for multiplication & Division equation: Let us understand this method with an example:

Example: What is the approximate value nearly to ‘x’?
89487  124 x 19808  594 x 40238  873 = x?
(a)1086888 (b) 1857122(c) 80388 (d) 549534

Step 1: Convert the exact values into approximate values.
89487  89500, 124  125, 19808  19800, 594  600, 
40238 40250, 873  875

Step 2: Put the approximate values in the equation.

Step 3: After solving the equation
x = 1086888.
1086888 is the approximate value of x. So, option (b) is very near about 1086888.

(iii) Method of approximation for square roots & cube roots:

Example: What is the approximate value of ‘x’?

(a)44 (b) 76 (c) 56 (d) 34

Step 1: Put the approximate values near the square root and cube root of an equation.
5342.045329,
5013.036  4913, 5847, 7734  , 10649.876 10648.

Step 2: Put the value approximate values in the equation.

Step 3: After solving the equation
x = 73 + 17-18+4

x = 76.
Note: To get the result very near about the exact answer we should always decrease or increase some quantities to make the balance.

We have discussed concepts of Simplification and Approximation techniques in our article.

Hope this was helpful

All the best!!!

Simplest way to Simplification

Rules of Simplification: Basic rule to solve any simplification equations is “VBODMAS”. To solve any simplification equation, we have to follow the above order.

V → Vinculum

B → Remove Brackets - in the order ( ), { }, [ ] 

Where, ( )→ common bracket or parentheses, { }→ braces , [ ] → square brackets

O → Of
D → Division

M → Multiplication

A → Addition

S → Subtraction

Note: At the time of opening of brackets, if a negative sign comes before the brackets then we have to change the sign of the expression inside the bracket.

Let us understand this concept with an example:

Example: Simplify:

= 894 + [87 - {182 ÷ 13 x 5 + 8 - (1-4)}]

= 894 + [87 – {182 ÷ 13 x 5 + 8 -(-3)}]

= 894 + [87 – {182 ÷ 13 x 5 + 8 +3}]

= 894 + [87 – {14 x 5 + 8 +3}]

= 894 + [87 – {70 + 8 +3}]

= 894 + [87 – {81}]

= 894 + [6]

= 900.

We have seen the simple method to solve the simplification problems, now we will discuss the approaches to solving the simplification problems by approximation.

Know more about numbers

Properties of number:

1. Commutative Property: This property tells us we can add and multiply numbers in any order.

(i) a + b + c = b + a + c

Ex.  3 + 5 + 6 = 5 + 3 + 6

In left hand side we add 3 & 5, and then we will get 8

In right hand side we add 5 & 3, and then we will also get 8.

8 + 6 = 6 + 8

14 = 14

L.H.S and R.H.S both are equal.

 

(ii) axbxc = bxcxa

5 x 6 x 7 = 6 x 7 x 5

In left hand side we multiply 5 & 6, and then we will get 30

In right hand side we add 6 & 7, and then we will also get 42.

30 x 7 = 42 x 5

210 = 210.

LHS and RHS both are equal.

 

2. Associative Property: Both addition and multiplication can be done with two numbers at a time.

(i)  a +(b + c)= (a + b) +c

Ex.  5 + (6 + 8) = (5 + 6) + 8

  5 + 14 = 11 + 8

19 = 19

Hence proved, LHS and RHS both are equal.

 

(ii)  ax (b x c) = (a x b) x c

Ex. 5 x (6 x 8) = (5 x 6) x 8

5 x 48 = 30 x 8

240 = 240

Hence proved, L.H.S and R.H.S both are equal.

 

3. Distributive Property: In this property "multiplication distributes over addition".

a x (b +c) = a x b + a x c

Ex. 5 x (6 + 8) = 5 x 6 + 5 x 8

5 x 14 = 30 + 40

70  = 70

Hence proved, L.H.S and R.H.S both are equal.

 

4. Identity property: It tells us that zero added to any number is the number itself. Zero is called the "additive identity." The identity property for multiplication tells us that the number 1 multiply by any number gives the number itself. The number 1 is called the "multiplicative identity."

Ex. a +0 = a

                       a.1 = a

5. Additive Inverse: The additive inverse of a number ‘a’ is the number that when added to ‘a’, yields zero. This number is also known as the opposite (number), sign change, and negation.

Ex.  a + (-a) = 0.

 

6. Multiplicative Inverse: It is reciprocal of a, denoted 1/a or a^-1.

Ex. a.1/a = 1

 

7. Additive Inverse: In this property, reverses the sign only.

Ex. a+ (-a) = 0.

 

Divisibility Rules: Divisibility means that you are able to divide a number evenly without using the long division.

Divisibility by 2: When the unit place digit of any number is 0,2,4,6 or 8 then the number is divisible by 2.

Ex. 10, 12, 1324, 13564, 434432, 9429372, etc.

 

Divisibility by 3: When the sum of digits of a number is divisible by 3 then the number is also divisible by 3.

Ex. 465981: 4+6+5+9+8+1= 33, which is divisible by 3, so 465981 must be divisible by 3.

 

Divisibility by 4: When the number formed by the last two digits of given number is divisible by 4 or it must be two or more zeros then the number is divisible by 4.

Ex.448, 1428, 33700, 4387920, etc.

 

Divisibility by 5: When the last digit of any number is either ‘5’ or ‘0’ is divided by 5.

Ex. 6742735, 3749370, 27629345, etc.

 

Divisibility by 6: When the number is divisible by 2 and 3 both then the number must be divisible by 6.

Ex. 356478, 82458474, 73834626, are divisible by 6.

 

Divisibility by 7: When the difference between the number formed by the digits other than the units digit and twice the units digit is either 0 or multiple of 7.

Ex. 798 is divisible by 7 because 79-2x8=79-16=63 is divisible by 7 and 798 is also divisible by 7.

 

Divisibility by 8: When the number formed by the last three digits of given number is divisible by 8 or it must be three or more zeros then the number is divisible by 8.

Ex. 848, 10128,323000, 438720, etc.

 

Divisibility by 9: When the sum of digits of a number is divisible by 9 then the number is also divisible by 9.

Ex. 39469581: 3+9+4+6+9+5+8+1= 45, which is divisible by 9, so 39469581 must be divisible by 9.

 

Divisibility by 11: When the sum of digits at odd and even places is equal or differs by a number divisible by 11, then the number is divisible by 11.

Ex. 7004844 is divisible by 11,  since

(Sum of digits at odd places) - (Sum of places at even places) = (7+0+8+4) - (0+4+4) = 19 - 8= 11.